k^2+1k+12=0

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Solution for k^2+1k+12=0 equation:


Simplifying
k2 + 1k + 12 = 0

Reorder the terms:
12 + 1k + k2 = 0

Solving
12 + 1k + k2 = 0

Solving for variable 'k'.

Begin completing the square.

Move the constant term to the right:

Add '-12' to each side of the equation.
12 + 1k + -12 + k2 = 0 + -12

Reorder the terms:
12 + -12 + 1k + k2 = 0 + -12

Combine like terms: 12 + -12 = 0
0 + 1k + k2 = 0 + -12
1k + k2 = 0 + -12

Combine like terms: 0 + -12 = -12
1k + k2 = -12

The k term is 1k.  Take half its coefficient (0.5).
Square it (0.25) and add it to both sides.

Add '0.25' to each side of the equation.
k + 0.25 + k2 = -12 + 0.25

Reorder the terms:
0.25 + k + k2 = -12 + 0.25

Combine like terms: -12 + 0.25 = -11.75
0.25 + k + k2 = -11.75

Factor a perfect square on the left side:
(k + 0.5)(k + 0.5) = -11.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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